3y/(y-2)-12/(y^2-2y)

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Solution for 3y/(y-2)-12/(y^2-2y) equation:


D( y )

y^2-(2*y) = 0

y-2 = 0

y^2-(2*y) = 0

y^2-(2*y) = 0

y^2-2*y = 0

y^2-2*y = 0

DELTA = (-2)^2-(0*1*4)

DELTA = 4

DELTA > 0

y = (4^(1/2)+2)/(1*2) or y = (2-4^(1/2))/(1*2)

y = 2 or y = 0

y-2 = 0

y-2 = 0

y-2 = 0 // + 2

y = 2

y in (-oo:0) U (0:2) U (2:+oo)

(3*y)/(y-2)-(12/(y^2-(2*y))) = 0

(3*y)/(y-2)-12*(y^2-2*y)^-1 = 0

(3*y)/(y-2)-12/(y^2-2*y) = 0

y^2-2*y = 0

y^2-2*y = 0

y*(y-2) = 0

y-2 = 0 // + 2

y = 2

y*(y-2) = 0

(3*y)/(y-2)-12/(y*(y-2)) = 0

(3*y*y)/(y*(y-2))-12/(y*(y-2)) = 0

3*y*y-12 = 0

3*y^2-12 = 0

(3*y^2-12)/(y*(y-2)) = 0

(3*y^2-12)/(y*(y-2)) = 0 // * y*(y-2)

3*y^2-12 = 0

3*y^2 = 12 // : 3

y^2 = 4

y^2 = 4 // ^ 1/2

abs(y) = 2

y = 2 or y = -2

y in { 2}

y = -2

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